\begin{tikzpicture}[sketch] %Achsen: \draw[->](0,-1)--(0,4)node[right, awesome]{branch cut}; \draw[->](-4,0)--(4,0); %Blauer Pfad %Nodes \node[inner sep=0pt] (LC) at (-3,0){}; \node[inner sep=0pt](RC) at (3,0){}; \node[inner sep=0pt](RL) at (89:3){}; \node[inner sep=0pt](rdl) at ($(RL)+(0,-1)$){}; \node[inner sep=0pt](LL) at (91:3){}; \node[inner sep=0pt](ldl) at ($(LL)+(0,-1)$){}; \node[inner sep=0pt](scc) at ($(90:3)+(0,-1.5)$){}; %RED CROSS \fill[awesome](scc) circle (0.07)node[label={[label distance=0cm]-20:$+ im$}]{}; \draw[awesome](scc)--++(45:0.2); \draw[awesome](scc)--++(-45:0.2); \draw[awesome](scc)--++(135:0.2); \draw[awesome](scc)--++(-135:0.2); \draw[awesome,line width=0.8mm](scc)--(0,3.8); %BLUE PATH \draw[->, dodgerblue](LC)--(-1.5,0); \draw[->, dodgerblue](-1.7,0)--(1.5,0)node[label={[label distance=-1.5cm]20:A}]{}; \draw[dodgerblue](1.3,0)--(RC) arc(-0.5:89:3)--(rdl);% arc(88:-260:0.5)--(LL) arc(91:180.5:3); \draw[dodgerblue]($(90:3)+(0,-1.5)$) circle(0.5)node[label={[label distance=0.25cm]10:$D \rightarrow 0$}]{}; \draw[dodgerblue](ldl)--(LL) arc(91:180.5:3); %Arrows: \draw[dodgerblue, ->](RC) arc(-0.5:45:3)node[label={[label distance=0cm]0:$B \rightarrow 0$}]{}; \draw[dodgerblue, ->](RL)--($(RL)+(0,-0.75)$)node[label={[label distance=-0.15cm]0:$C$}]{}; \draw[dodgerblue, ->]($(LL)+(0,-1)$)--($(LL)+(0,-0.25)$)node[label={[label distance=-0.15cm]200:$C=E$}]{}; \draw[dodgerblue, ->](LL) arc(91:135:3)node[label={[label distance=0cm]180:$0 \leftarrow F$}]{}; %BLACK NODES \fill(LC) circle(0.05); \fill(RC) circle(0.05); \fill(RL) circle(0.05); \fill(rdl) circle(0.05); \fill(ldl) circle(0.05); \fill(LL) circle(0.05); \draw[<->, teal](45:0.15)--(45:2.85)node[label={[label distance=0.5cm]270:$R \rightarrow \infty$}]{}; \draw[teal](scc)--++(200:0.5)node[label={[label distance=-0.3cm]200:$0 \leftarrow \varepsilon$}]{}; \node at (0,-2){$\lim\limits_{\substack{R\to\infty\\\varepsilon\to 0}}\displaystyle\oint\ldots=A+C+E\stackrel{\text{Cauchy}}{=}0$}; %\draw[dodgerblue](0,1.98) arc(88:-90:0.5); \end{tikzpicture}